(t-5)^2=2(5-t)

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Solution for (t-5)^2=2(5-t) equation: 



(t-5)^2=2(5-t)

We move all terms to the left:

(t-5)^2-(2(5-t))=0

We add all the numbers together, and all the variables

(t-5)^2-(2(-1t+5))=0



We calculate terms in parentheses: -(2(-1t+5)), so:

2(-1t+5)

We multiply parentheses

-2t+10

Back to the equation:

-(-2t+10)



We get rid of parentheses

(t-5)^2+2t-10=0

We add all the numbers together, and all the variables

2t+(t-5)^2-10=0

We move all terms containing t to the left, all other terms to the right

2t+(t-5)^2=10

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